Of course it is possible. But then it is not YAML anymore. 
use YAML;
%test = (k1 => "v1",
         k2 => "v2");
$dump = Dump \%test;
$dump =~ s/^---/test:/;
print $dump;

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In reply to Re: Problem using YAML by choroba
in thread Problem using YAML by Pazzeo

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