It shows up as const AV in the opcode tree.

You can prove the list is flattened once using 

for (1..2) {
   for ((), 4..8) {
      say $_++;
   }
}

[download]

Update: Added missing parens.

In reply to Re^5: Why is const x const not a const? by ikegami
in thread Why is const x const not a const? by PerlGrey

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