Sorry, there was a set of parens missing. (Fixed.) I was about to reply to your post that for (CONST..CONST) is a counting loop rather than a loop iterating over the result of a range operator. There is no range operator, so the range operator cannot be flattened. Try 

perl -e"<>; exit; @a = 1..100000;"
perl -e"<>; exit; for ((), 1..100000) {}"

[download]

Results: 

perl -e"<>; exit; for ((),1..   1000) {}    1,252K
perl -e"<>; exit; for ((),1..  10000) {}    1,784K
perl -e"<>; exit; for ((),1.. 100000) {}    6,028K
perl -e"<>; exit; for ((),1..1000000) {}   45,212K

[download]

Update: Added results.

In reply to Re^7: Why is const x const not a const? by ikegami
in thread Why is const x const not a const? by PerlGrey

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