Yes, I forced the use of the range operator. After all, we are talking about the range operator. I didn't say «for (CONST..CONST)» flattens; I said «CONST..CONST» does, and I was referring to the range operator.

In reply to Re^9: Why is const x const not a const? by ikegami
in thread Why is const x const not a const? by PerlGrey

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