Hi, I am pretty much a newbie to perl. Here is my question...
I understand that `grep xyz anyfile` can be expressed as
   while <anyfile> {
     if (/xyz/) {
      print $_;
       }
      }

[download]
But how would I approximate grep -v in perl?
When I use (!/xyz) I am getting some strange results, namely every line of the file is being displayed with the one line that does not match "xyz" being displayed twice at the end of the output. I should also mention that I am using a foreach $i (@list) where @list = qw (leroy brown). I am sure that I am not using the $_ variable correctly but I don't know exactly what it is that I am doing wrong.
 SCRIPT:

  #!/usr/bin/perl -w
  @list = qw (leroy brown);
  $log="/home/psmith/logfile";
  open IN (<$log);
  while <IN> {
   foreach $i (@list){
    if (!/$i/) {
     print $_;
     }
    }
   }

 OUTPUT:

 the quick brown fox jumped over the lazy dogs
 leroy black the badest man in the whole damn town
 live long and prosper
 live long and prosper

[download]

Any help would be appreciated!

Thanks


Edit 2001-07-09 ar0n -- New title

In reply to Unix 'grep -v' equivalency in Perl (was: Perl Regex Question) by quasimojo321

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