The expression $english && $foreign will evaluate to either true (1) or false ("") but will never be equal to '-1'.

Wrong. The "&&" operator doesn't return 1 or "". It returns the expression on the right side of "&&" if and only if both expressions are true.

use 5.010;
my $english = 'foobar';
my $foreign = -1;
say ($english && $foreign);  # says "-1"
say ($foreign && $english);  # says "foobar"

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In reply to Re^2: Hash Printing reveals Hash Memory Location by tobyink
in thread Hash Printing reveals Hash Memory Location by perlStuck

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