I guess what I was missing is that "SUPER" isn't as magical as I thought. I understand that
$c->$m($x) is just
$m($c, $x) but I was reading "SUPER" as somehow being associated to the class, not being part of the method. To abuse some notation, I was reading "
$c->SUPER::get" as more like "
($c->SUPER)::get" than like "
$c->(SUPER::get)". That's not right;
functions are the real things, and
classes are the illusion.
At http://perldoc.perl.org/perlobj.html#Method-Invocation it says "...you may use the SUPER pseudo-class to tell Perl to start looking for the method in the packages named in the current class's @ISA list." When I've read that in the past, I guess I thought "current" referred to "that thing just to the left of the '->'" but it means "the thing after 'package' up above".
I feel like I understand better now.
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