The problem is that '$array' is not an array; it's an array reference - similar to a pointer. Your code seems fine, all except for that point. Quick overview of dealing with array references:

# Turning an arrayref into an array
my @arr = @$aref;
# Extracting a single value from an arrayref
print ${$aref}[0];
# Or, more readable and less problematic:
print $aref -> [0];
# Looping over the pointed-to list
for my $i (@$aref){
    ...
}
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In the above case, the structure that you're getting back from 'Range()' is an "AoA" - an array of arrays - which looks like this:

$aref = [
          [
            1,
            2,
            3
          ],
          [
            4,
            5,
            6
          ],
          [
            7,
            8,
            9
          ]
        ];
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Notice the second level of indirection, there? The result is that just converting the ref to an array is going to give you a list of... arrayrefs, which need to be expanded into arrays. The solution that netwallah shows is correct - I just wanted to give you a more general heads-up for this kind of problem. So, expanding the above looks like this:

for my $deref (@$aref){
    for my $element (@$deref){
        print "$element\n";
    }
}
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Again, for more on data structures - AoAs, HoHs, etc. - see perldoc perlref and the excellent Data Structures Cookbook.

-- 
I hate storms, but calms undermine my spirits.
 -- Bernard Moitessier, "The Long Way"