Inside the sort block, $a and $b are elements of @bigArray, not indexes into it.

So if @bigArray contains array refs, both $a and $b end up being an array ref. And you can dereference and index into an array with the $a->[$index] syntax.

On the other hand if you write [$a], you wrap the array ref in $a into another array ref -- not what you want.

See perlreftut and perlref for more details.

Perl 6 - second systems done right

In reply to Re^3: this doesn't sort by moritz
in thread this doesn't sort by hsfrey

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