Hi, Requirement - I have file name called "Rajesh.1202242219". Numbers are nothing but a date "`date '+%y''%m''%d''%H''%M'`" format. Now I am trying to write a perl script to extract the numbers from file name and compare with current system date and time and based on output of this comparison, print some value using perl. Approach: Extract the Digit from File name: 
 if ($file =~ /Rajesh.(\d+).*/) {
    print $1;
            }

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Convert this time into readable time in perl 
my $sec  =  0;    # Not Feeded
my $min  =  19;
my $hour =  22;
my $day  =  24;
my $mon  = 02   - 1;
my $year = 2012 - 1900;
my $wday = 0;    # Not Feeded
my $yday = 0;    # Not Feeded

my $unixtime = mktime ($sec, $min, $hour, $day, $mon, $year, $wday, $y
+day);
print "$unixtime\n";
my $readable_time = localtime($unixtime);
print "$readable_time\n";

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find Current time and compare... 
my $CurrentTime = time();
my $Todaydate = localtime($startTime);

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But the problem here is, I am not getting solution of how to extract 2 digit from $1 and assign to $sec, $min, etc... Any help????? Also, if you have good approach for this problem statement, Please share with me

In reply to Convert Old Unix Date to Perl and compare by rajeshatbuzz

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