In this case, $year is already in "year-1900" format so that value can be used as is.

I'm assuming you meant +1900 and not +100 since that makes no sense at all?

Edit: Nevermind me. I just woke up.

-- Time flies when you don't know what you're doing

In reply to Re^2: Convert Old Unix Date to Perl and compare by FloydATC
in thread Convert Old Unix Date to Perl and compare by rajeshatbuzz

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