Hello, I'm new here and let me apologize for any inconvenience regarding this post.
so, my question is that I'm trying to make a script that reads 2　arguments and returns result of bit-wise operation AND.

#!/usr/bin/perl
use strict;
use warning;

my $arg00=shift ( @ARGV );
my $arg01=shift ( @ARGV );

#printf $arg00+$arg01."\n";
printf sprintf( $arg00&$arg01 )."\n";

[download]

when I run test.pl 33 224, it returns result as 22.
if I run printf sprintf( 33&224 )."\n"; it returns 32. also if I comment out the # before the printf, it also returns 32.
could any one give me an advice about this difference?
regards,
toro

In reply to bit-wise operation by toro_the_third

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