Both strings evaluate to zero in numeric context (as they cannot be parsed as numbers), and thus are numerically equal. With warnings enabled, you'd get
$ perl -wle "print 1 if 'you' == 'me'" Argument "me" isn't numeric in numeric eq (==) at -e line 1. Argument "you" isn't numeric in numeric eq (==) at -e line 1. 1
In reply to Re: Definition of numerically equal and rationale for 'you' == 'me'
by Eliya
in thread Definition of numerically equal and rationale for 'you' == 'me'
by andreas1234567
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