Even in an imaginary Perl without sigils, the following code could be parsed unambiguously:
No, it cannot. Stepping away the additional problem with say (the first x can be seen as a filehandle), you're forgetting that sigils make barewords possible. You're x x x can be parsed in several ways: 
$x x $x
x(x($x))
x::->x("x")

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or some combination there off. That is, if we'd dropped sigils, a bare x can be a (scalar) variable, an operator, a class name, a subroutine, or the string "x".

In reply to Re^8: Definition of numerically equal and rationale for 'you' == 'me' by JavaFan
in thread Definition of numerically equal and rationale for 'you' == 'me' by andreas1234567

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