Very similar to what I've done,
but note that (at least in my terminal) you can't sub the tab for spaces, since it have a changing length based on previous characters.
Here's my version (I only needed columns this time):
my prntOffset = 0;
sub prink #(string to print)
{
my $prntText = shift;
print $prntText;
if($prntText =~ s/.*[\n\r](.*)$/$1/s){$prntOffset = 0;}
while(length $prntText)
{
if($prntText =~
s/^((\w|[\Q\\\/\{\};'"\[\]\.,\?\~\!@#$%^&* ()\E])+)//
)
{$prntOffset += length $1;} #normal chars
elsif(substr($prntText,0,1) eq "\b")
{
$prntText = substr($prntText,1);
$prntOffset-- if $prntOffset;
}
elsif($prntText =~ s/^(\a+)//){} #yes nothing
elsif($prntText =~ s/^(\t+)//)
{$prntOffset += 8 * (length $1) - ($prntOffset % 8);}
else
{
die "\ano pattern match for
\"".substr($prntText,0,1)."\" in \"prink\" function\n";
}
}
$prntOffset %= 80;
}
Seems to hold for the few but focused tests I ran.
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