I am still struggling very much with killing the process once it has timed out. This is what I have: 

sub runFile2 {
  local($fileName, $timeout) = @_;
  my $child_pid;
  local $SIG{ALRM} = sub {
    $didTimeout=1;
    print OUTPUT "timeout";
    print OUTPUT "-", $child_pid;
    kill 9, $child_pid;
  };
  if ($child_pid = fork ) { # create child
    $didTimeout=0;
    alarm $timeout;
    $start=gettimeofday();
    waitpid($child_pid, 0); # Wait for child to terminate
    alarm 0;
    $end=gettimeofday();
    if($didTimeout==0) {
      print OUTPUT $end - $start;
    } else {
      kill 9, $child_pid;
    }
  } elsif (defined $child_pid) {
    $cmd = "$solver1 $fileName >> output.txt";
    exec ($cmd);
    exit;
  } else { # Something terrible has happened, as fork failed
      die "Cannot fork!\n";
  }
}

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It may not be the best way because I've just been trying anything I can find. The code will timeout the function, but not kill it. Any suggestions? Help would be greatly appreciated. I've tried everything I can find online without success. Thanks!

In reply to Re^6: Timeout and kill by nelson64
in thread Timeout and kill by nelson64

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