There were several errors, but the main one was declaring a second @ten_array inside the loop. Others were:

  1. Initialising @ten_array with 0 which doesn't clear the array as I guess you were thinking, but assigns 0 as the first element
  2. Declaring square nested. It will not work as you expect
  3. Assigning $number to @ten_array. Even if you hand't redeclared @ten_array that wouldn't have worked because it simply replaces any previous content of the array with a single element containing $number.
  4. You use $number as a global inside square, but you call square passing a value into it. Usage and implementation are not consistent.

A cleaned up version of your code with a few other changes is shown below. Note in particular the use of strict (always use strictures) and a Perl for loop to count the loop iterations instead of hand roling a while loop to do that.

#!/usr/bin/perl use strict; use warnings; my $wanted = 3; my @numbers; print "Enter $wanted numbers.\n"; for (1 .. $wanted) { my $number = <>; chomp($number); push @numbers, $number; square($number); } print "The ten numbers were @numbers\n"; sub square { my ($number) = @_; my $square_num = $number * $number; print "$number squared is: $square_num\n"; }
True laziness is hard work

In reply to Re: Storing 10 numbers in array by GrandFather
in thread Storing 10 numbers in array by snakeyes52

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