I would convert "Foo" to \&Foo without using an eval by using a closure: 
#!/usr/bin/perl -l

use strictures 1;
use Devel::SimpleTrace;

sub Foo {
        use strict 'refs';
        use warnings;

        my $x = shift();
        return sub { 
                my $y = shift();
                print "$x, $y!";
        }
}

use strict 'refs';
my $h = Foo("Hello");
my $g = Foo("Goodbye");
print &$h("Bar");
print &$g("Baz");

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In reply to Re: Sub ref from string without eval by Khen1950fx
in thread Sub ref from string without eval by lackita

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