If you want to perform a bitwise AND with a Perl integer, the first 16 or 24 "characters" of your hex string will disappear anyway, as your integer will be limited to 32 or 64 bits. So, your result is going to be: 
hex(substr($hex,  -8)) & $integer;   # Perl with 32-bit integers
hex(substr($hex, -16)) & $integer;   # Perl with 64-bit integers

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In reply to Re: Bitwise AND with large numbers by JavaFan
in thread Bitwise AND with large numbers by mdej

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