Ugh, I'm so silly. Even after I learned what /o does at YAPC, from Dominus. I0's example answers the question.

As for what /o does, it means "do not compile this again." What it does get that done is this:
print "trying...\n"; $x = qr/japhy/o; print $you =~ $x; # makes a tree like [print "trying\n"] [compile regex /japhy/] [return regex (some internal form)] [match regex on $you] [print] # the /o modifier tells [return regex] to MODIFY the tree [print "trying\n"] -------------------\ [compile regex /japhy/] | [return regex (some internal form)] <-/ [match regex on $you] [print]
That's what happens. The op-tree is modified because of the /o modifier. Perl never sees the "compile this regex" op again, and instead, it uses some pre-compiled regex.

japhy -- Perl and Regex Hacker

In reply to Re: qr//o ... "o"?? by japhy
in thread qr//o ... "o"?? by tye

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