If the name is in $data->{name} then your 2nd bit of code starts off right ($name = $data->{name}) but the print-command afterwards isn't. Try print "$name is $data->{age} years old.\n"
Suppose $data->{name} contains the name 'Jos'. When you're storing that in $name, the print-statement tries to access $data->{Jos} which is very unlikely to exist in your XML-data. So your code probably doesn't print a name at all.

In reply to Re: need help with xml parser by Neighbour
in thread need help with xml parser by nepzraaz

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