If you look at his spec, he wants more than one "out" file. In each directory, he wants a file named 'list' that contains a list of every subdirectory of that directory. So in a directory structure like the following, you would get 'list' files like so: 

$ find . -ls|cut -b14-24,68-
drwxr-xr-x  .
drwxr-xr-x  ./a
-rw-r--r--  ./a/list
drwxr-xr-x  ./a/d
drwxr-xr-x  ./a/c
drwxr-xr-x  ./b
-rw-r--r--  ./list
$ cat list
a
b
$ cat a/list
c
d

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Aaron B.
Available for small or large Perl jobs; see my home node.

In reply to Re^5: listing all subdirectories of directory into file by aaron_baugher
in thread listing all subdirectories of directory into file by tevolo

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