Hi Monks, please check the code as it's working fine for hard coded path but for generic path it's not working, it says "Can't read the file". Please check and let me know where am I lagging: 
#!/usr/bin/perl
use warnings;
use strict;

print "Enter the path where the log file is placed : ";
my $dir =<>;
chomp($dir);
opendir DIR, $dir or die "cannot open dir $dir: $!";
my @files= readdir DIR;
my $len=scalar(@files);
print $len;
print "Enter the path where to save the report";
my $dest_dir = <STDIN>;
chomp($dest_dir);
open(FH1,">$dest_dir./result.txt") if( $len > 0);
foreach my $file (@files){
    if($file=~/\.txt/){
        print "$file\n";
        open(FH,"$file") or die "Can't read the file \n";
        while(my $line= <FH> ){
            print FH1 $line;
        }
        close FH;
    }
}
close FH1;
closedir DIR;

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UPDATE: My program is in C:\Perl\bin and I'm entering the path to read & write files as C:\Perl where it gets failed but if I use C:\Perl\bin then it works fine. How to fix this issue?

In reply to Unable to read a file by ckj

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