If a change is made in the perl program during run time before that line is actually interpreted, why it is not reflected.? eg. In the below perl code, 
        $n1=5;    #any numeric value
    $n2=10; #any numeric value
    $result = $n1 * $n2;
    print "$result";

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while running the code, i changed the operator from * to + ie. $n1 + $n2.But still the result is for only multiplication. As far as I understand, no object output file is created during compilation of perl code and While running the code , each line is interpreted and executed before proceeding to next line. So, changes in any line of the code, before the line is interpreted, should be refleceted in output. Is my understanding correct ? Or is there any other way , execution of perl script happens ?

In reply to Perl execution by rbala

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