I am not sure I undestand your question.
First of all, you example does not work. Precisely for the reason you give: the @ in this case is interpreted as a list1 variable introducer.
Use single quotes if you do not want variables to be interpolated in a string:
$x = 'jdoe@somewhere.com,bdoakes@nowhere.com';
To create a list
1 of two e-mail addreses from this, you can use
split:
@addresses = split /,/, $x;
1Or, to be exact, an array.
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