Hello jwkrahn

I have just read perlpacktut and I would like to have some clue for my 2 questions about this thread.

What OP does is in short... 

printf "0x%x\n",                #print it as hex
    unpack("N",                 #unpack it as 32bit int ,big endian
        pack("B32",             #pack it as MSB 32bit integer
            sprintf("%032s",    #32 length bit string
                join('',
                    @rand1))));

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1. Does it really MSB ?

MSB should pad '0' for right side, not left side, doesn't it ? 
my @rand1 = qw( 1 );
this currenty goes "00000000000000000000000000000001". Is it OK?

2. How oct insures it is MSB and 32bit big endian?

Does oct thinks it as 'long long' seeing the size of $Config{longlongsize}? How it thinks for MSB? 
use Config;
print "int size=".$Config{intsize}."\n";
print "short size=".$Config{shortsize}."\n";
print "long size=".$Config{longsize}."\n";
print "long long size=".$Config{longlongsize}."\n";

[download]
If I could have some explanations by you or other monks, I am glad.

In reply to Re^2: array of binaries to hex conversion by remiah
in thread array of binaries to hex conversion by bebe

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