Thanks for reply. Stories of bit is a little bit hard for me. Please point out if I am saying something wrong.
How/what?
I was wrong. I was confused with little endian and big endian. Here OP expects it's input bit array as Big Endian(N) and descending bit order(B).
printf "0x%x\n", #hex
unpack("N", #unpack it as 32bit int ,big endian
pack("B32", #pack it as MSB descending bit, 32bit inte
sprintf("%032s", #32 length bit string
join('',
@rand1))));
So, left pad works fine, even if it was an array of 16bit.
my $num;
$num=pack('n',7); #16bit short Big endian, it's value is 7
printf "big endian, descending bit order:%s\n", unpack('B16',$num);
printf "big endian, ascending bit order:%s\n", unpack('b16',$num);
printf "unsigned short=%d\n",unpack('n',pack('B16', unpack('B16', $num)));
printf "right pad:%s\n", unpack('B16',$num) . '0' x 16;
printf "32bit right pad=%d\n",unpack('N',pack('B32', unpack('B16',$num) . '0' x 16));
#==> this prints "32bit right pad=458752"
printf "left pad:%s\n", '0' x 16 . unpack('B16',$num);
printf "32bit left pad=%d\n",unpack('N',pack('B32', sprintf('%032d', unpack('B16',$num)))
#==> this prints "32bit left pad=7"
You are the same anonymous with this.
print '0x'. unpack 'H*', pack("B32", substr("0" x 32 . join('',@rand1), -32));
So, you are going to say: If you need it's hexadecimal values, there is no need for decimal( unpack 'N') -> hexadecimal conversion( printf %x), just print it as hex( unpack 'H'). In reply to Re^4: array of binaries to hex conversion
by remiah
in thread array of binaries to hex conversion
by bebe
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |