I always use 1 while s///;, but you can also get that behavior with only using s///;: 

my $data = "aaaaaaaaaaaaaaaaaaaaaaa"; # 23 a's
$data =~ s/aa/pos() = print a/ge;
print $data;

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This outputs a in stead of aaaaaaaaaaaa

pos() normally returns the position where the regexpr matched the last time. Normally the s/// operator leaves of at that position. By using pos() as a lvalue you can reset this position. Therefore the s/// operator starts all over, mimmicking the 1 while s///g behavior.

I wouldn't use this under normal circumstantions though, since this is kind of a obfu. ;)

In reply to Re: replacing text you have already replaced... by wine
in thread replacing text you have already replaced... by suaveant

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