Consider the following option:

use strict;
use warnings;
use Regexp::Common;

my %numbers;
open my $fh, '<', 'numbersFile.txt' or die $!;

while (<$fh>) {
    $numbers{$1}++ while /($RE{num}{real})/g;
}

close $fh;

print "Number: $_\tCount: $numbers{$_}\n"
  for sort { $a <=> $b } keys %numbers;

[download]

Contents of numbersFile.txt:

12.7 abce -3.14 21
This is a line with 8 words in it.
10000 is a big number.
Looks like 21 and 12.7 again.
5 + 7 = 12

[download]

Output:

Number: -3.14    Count: 1
Number: 5    Count: 1
Number: 7    Count: 1
Number: 8    Count: 1
Number: 12    Count: 1
Number: 12.7    Count: 2
Number: 21    Count: 2
Number: 10000    Count: 1

[download]

Regexp::Common is used (the $RE{num}{real} in the regex) to capture the numbers on each line that's read. You may not need to use it, if the numbers are just sets of decimals integers, in which case \d+ can be used, instead.

The while before the regex insures processing all numbers on a line. The anonymous subroutine { $a <=> $b } is used to sort numbers.

Hope this helps!

In reply to Re: counting elements using a hash by Kenosis
in thread counting elements using a hash by bk1388

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