In addition to the other bugs, I think:
for ( @nvalue ) {
print "$_\n$_[0]\n$_[0]->[0]\n";
$d++;
print join(", ",$_[$e]->[$d]);
}
print "\n";
should be written as:
for ( @nvalue ) {
print "$_\n$_->[0]\n$_->[0][0]\n";
$d++;
print join(", ",$_->[$e][$d]); # XXX: join() ?
}
print "\n";
The problem is that
$_[0]
means "element 0 of the
@_ array", whereas
$_->[0]
means "element 0 of the array referred to by
$_".
_____________________________________________________
Jeff japhy Pinyan:
Perl,
regex,
and perl
hacker.
s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;
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