Hello perltux, and welcome to the Monastery!

How do I get the second pattern match to assign all matches as multiple elements to the array?

I think you need to capture the multiple matches first, then separate them using a loop:

my @chunks = $sysex_dump =~ /\xF0C.[~z]((?:..LM  0087[A-Z][A-Z].+?)+)\
+xF7/gs;
my @parts;

for (@chunks)
{
    push @parts, $1 while /(..LM  0087[A-Z][A-Z].+?)/gs;
}
[download]

This code is untested (you provided no sample data), but it should give you a workable approach. Note that in the first regex, the second + quantifier needs to be within the capturing parentheses, so I have added non-capturing parentheses (?:) to define this quantifier’s scope.

Update: I see you have added a “self contained code example” to your original post. From this, it appears that the data to be matched contains literal . characters (periods, full stops.) But your regex matches these with:

  (..LM  0087[A-Z][A-Z].+?)
#  ^^ <= here they are
[download]

which matches any two characters. To match periods only, backslash them in the regex:

/\xF0C.[~z](\.\.LM  0087[A-Z][A-Z].+?)+\xF7/s
[download]

Hope that helps,

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