Thank you Choroba Sir for your interest , please have a look at C code.

#include<stdio.h>
#include<conio.h>
void main()
{
int a[20],b[20],c[20],i,j=0,k=0,n;
clrscr();
printf("Enter the number of elements");
scanf("%d",&n);
printf("Enter  n numbers\n");
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
{
if((a[i]%2)==0)
{
b[j]=a[i];
j++;
}
else
{
c[k]=a[i];
k++;
}
}
printf("The  even numbers  are\n");
for(i=0;i<j;i++)
{
printf("%d\n",b[i]);
}
printf("The odd numbers are\n");
for(i=0;i<k;i++)
{
printf("%d\n",c[i]);
}
getch();
}

[download]
It will basically input an array of 'n' numbers and then separate it into two arrays, one contains odd numbers and one contains even numbers. Hoping to hear from you soon.

In reply to Re^2: New student, can we write this program in perl... by rahulraina7
in thread New student, can we write this program in perl... by rahulraina7

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