Zitoune has asked for the wisdom of the Perl Monks concerning the following question:
$zipfile="$Inbox"."\\"."$x"; $zip=Archive::Zip->new($zipfile) or die "Unable to Open the Fi +le : $zipfile\n"; for $x ( $zip->members() ) { $zip->extractMemberWithoutPaths($x); }
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Re: Path Of an extracted Files
by chip (Curate) on Mar 11, 2004 at 17:58 UTC | |
by Zitoune (Beadle) on Mar 11, 2004 at 18:02 UTC | |
by chip (Curate) on Mar 11, 2004 at 18:04 UTC | |
by Zitoune (Beadle) on Mar 11, 2004 at 18:10 UTC | |
by chip (Curate) on Mar 11, 2004 at 18:12 UTC | |
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by arden (Curate) on Mar 12, 2004 at 18:07 UTC | |
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Re: Path Of an extracted Files
by Zitoune (Beadle) on Mar 11, 2004 at 18:11 UTC | |
by graff (Chancellor) on Mar 12, 2004 at 04:49 UTC |