Re: how do I use a hash of hashes reference in a function ?

$hashref{name}={data1=>"moredata",};
[download]

Wrong syntax for adding to a hash. Use this:

$hashref{name}{data1} = "moredata";
[download]

Comment on Re: how do I use a hash of hashes reference in a function ? Select or Download Code

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RE: Answer: how do I use a hash of hashes reference in a function ? by Fastolfe (Vicar) on Sep 22, 2000 at 23:45 UTC
Just for clarification (for the original poster), your syntax: `$hashref{name} = { data1 => "moredata" };` [download] replaces the reference in `$hashref{name}` with a new one, composed of your `data1 => "moredata"` hash. That's why it won't work. merlyn is correct in that if you wish to modify the hash referenced by `$hashref{name}` you don't do that by setting `$hashref{name}`, you modify it as if it were a hash: `$hashref{key}{subkey} = $xyz;`	[reply] [d/l] [select]

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$hashref{name} = { data1 => "moredata" };
[download]

$hashref{name}

data1 => "moredata"

$hashref{name}

$hashref{key}{subkey} = $xyz;