in reply to system() with timeout

See Safety of using alarm.

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Re: Re: system() with timeout
by Sprad (Hermit) on Mar 18, 2004 at 16:18 UTC
    Dang. I'm stuck with 5.6.1, so it looks like the alarm method isn't going to work for me...

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    A fair fight is a sign of poor planning.

      Why not. 5.6.1 supports alarm, just not on Win32.

      cheers

      tachyon

        Under Win32, create a separate thread and start your external process under that thread. Back in the parent thread, start counting until you want the timout to expire (or Wait() for it) then kill the thread. It looks something like this:
        Win32::Process::Create($proc, "c:\foo.exe", "foo.exe arg1 arg2 arg3", 0, $priority, ".") || die "can't create process, ". Win32::FormatMessage( Win32 +::GetLastError()); my $ret= $proc->Wait($timeoutsecs * 1000); if (! $ret ) { # Still running, kill it. $proc->Kill(0); }
        According to the thread linked above, signals are unsafe in version below 5.8. (and I am using Win32, so even then...)

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        A fair fight is a sign of poor planning.