No. As perlref says, Only package variables (globals, even if localized) are visible to symbolic references. Lexical variables (declared with my()) aren't in a symbol table, and thus are invisible to this mechanism.
If you want to access lexical variables, you have to do a lot of mucking around with internals. Modules (like PadWalker) can get rid of most of that for you. But I don't think that this module will actually create new lexical variables in the previous scope. Perhaps some module will do it. If not, then I'd bet that it is possible for someone knowledgable to write such a beast.
However actually using it would not be recommended... | [reply] |
You would have to do it with eval:
use strict;
use warnings;
my $ref;
my ($A,$B);
while (<DATA>) {
chomp;
if (s/^\s+//) { eval "\$$ref = $_" }
else {$ref = $_}
}
print "A=$A and B=$B\n";
__DATA__
A
33
B
22
The PerlMonk tr/// Advocate
| [reply] [d/l] |
No, no, that's cheating.You cannot predeclare my ($A,$B) as you are not supposed to know what's in the data-file. It could be any variable name and any value. However, the eval suggestion is a good one. How about:
$name ='A';
$value =10;
$string = 'my $' . $name . '=' . $value . '; print "result inside eval
+: $A\n";';
eval ($string) or die "ERROR: $@";
print "result outside eval: $A\n";
As can be expected the lexical declaration does not survive outside of the eval though :-(
CountZero "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law
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