Re: Regex Needed

m/(\w+) (?=FOUND)/g;

have a look at perldoc perlre where look-ahead is mentioned. The example there quite matches your problem.

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Re: Re: Regex Needed by TilRMan (Friar) on Mar 25, 2004 at 02:15 UTC
I think the OP has a different definition of "word" than Perl does -- in particular, a word can contain a colon. My guess is that the OP wants a word to be any non-whitespace. `m/(\S+)\s+FOUND/; # The word is now in $1` I don't see the need to use lookahead for this regex. -- LP^>	[reply] [d/l]
Re: Re: Regex Needed by ysth (Canon) on Mar 25, 2004 at 02:07 UTC
That would work, but if the goal is to have the entire match ($&) be the desired word, it should be `m/\w+(?= FOUND)/g` [download] If capturing into $1 is the goal, `m/(\w+) FOUND/g` [download] is all that is needed.	[reply] [d/l] [select]