Re: RE: RE: RE: RE: Passing named parameters

Sorry to reply 4 years later. The - has nothing to do with the string or bareword. The => says qoute whats on my left and pretend i'm a comma. so a(-beer=>none) is the same as a("beer", none); Perhaps this is what the original author meant but I wasn't sure and thought i might clarify a bit.

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Eric Hodges

Comment on Re: RE: RE: RE: RE: Passing named parameters

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Re: Re: RE: RE: RE: RE: Passing named parameters by perlmonkey (Hermit) on Apr 09, 2004 at 01:19 UTC
I assume that "is the same as a('beer', none)" is a typo, ... and that you meant "is the same as a('-beer', 'none')" And since we are clarifying ... the '-' is part of the key (or the first argument, depending on how you look at it). `bash$ perl -w -Mstrict -MData::Dumper -e \ "print Dumper( { -name => 'foo', -value => 'bar' } );"` [download] Results: `$VAR1 = { '-name' => 'foo', '-value' => 'bar' };` [download]	[reply] [d/l] [select]

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Re: Re: RE: RE: RE: RE: Passing named parameters
by perlmonkey (Hermit) on Apr 09, 2004 at 01:19 UTC

is the same as a('beer', none)

is the same as a('-beer', 'none')

bash$ perl -w -Mstrict -MData::Dumper -e \
"print Dumper( { -name => 'foo', -value => 'bar' } );"
[download]

Results:

$VAR1 = {
          '-name' => 'foo',
          '-value' => 'bar'
        };
[download]

[reply]
[d/l]
[select]