Re: Regular expression substitution question

Sure it can be done ...

$output =~ s/\x7E(?!$)/\x7D\x5E/g;
[download]

See perlre where it talks about zero-width lookaheads

Comment on Re: Regular expression substitution question Download Code

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Re: Re: Regular expression substitution question by Roy Johnson (Monsignor) on Mar 31, 2004 at 19:01 UTC
And for us anal-retentive types who hate to replace something with itself: `s/(?<=\x7E(?!$))/\x5E/g;` [download] Oh, just shoot me now. I didn't notice 7E->7D. I must not be anal-retentive enough. Thanks, Enlil. `s/~(?!$)/}^/g;` [download] The PerlMonk `tr///` Advocate	[reply] [d/l] [select]
Re: Re: Regular expression substitution question by rduz (Initiate) on Apr 01, 2004 at 03:08 UTC
Thanks for the answers. This indeed works quite well.	[reply]