in reply to Try your luck at Superenalotto!

Just for grins, I calculated the odds...I think it's right! The stats given are for getting exactly that many numbers correct. 
    

  1. 235054512 in 622_614_630
    2. 

  2.  33388425 in 622_614_630
    3. 

  3.   2046800 in 622_614_630
    4. 

  4.     53550 in 622_614_630
    5. 

  5.       504 in 622_614_630
    6. 

  6.         1 in 622_614_630
    7.
To get the stats for at least that many numbers correct, add up all the results below the number in question. For instance, to get at least two numbers, you'd add up the stats for 2, 3, 4, 5, and 6 numbers correct.

thor

Update: In case anyone cares, the formula I used was choose(6,n)*choose(90-n-1,6-n)/choose(90,6) where choose(n,r) is defined as n!/(r!(n-r)!).

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Re: Re: Try your luck at Superenalotto!
by QM (Parson) on Apr 30, 2004 at 02:08 UTC
    Shouldn't the odds of getting at least one right add up to 622_614_630?

    -QM
    --
    Quantum Mechanics: The dreams stuff is made of

[reply]
      If I understand your question: no. There are a whole lot of opportunities to get none right, as is evidenced by my own lottery playing experience...:)

      thor

[reply]

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