Re: Getting the next array element while still keeping the current one

I'm responding to the minor gripes that my code whines about "Use of uninitialized value in concatenation (.) or string..." under use warnings;.

The only place where it complains is the print statement, which was intended to be a sample - the print was to be replaced by real code.

The undef values in $p and $n are ligitimate for those boundary conditions.

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Comment on Re: Getting the next array element while still keeping the current one

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Re: Re: Getting the next array element while still keeping the current one by parv (Parson) on May 05, 2004 at 04:58 UTC
Yes, no question about the fact of two values being undefined. I just wanted to clear the things, at least for myself; thanks.	[reply]