in reply to Re: Regex to detect and remove a linebreak in an URL
in thread Regex to detect and remove a linebreak in an URL

[^\w\s] matches all characters that are not both a word character and a whitespace character. That is, it matches *any* character. Which means that from the string <URL:http://www.example.com/> your first regex is going to match http://www.example.com/>. Your second regex is only going to match if the string contains http: followed by a sequence of non-whitespace characters, followed by a whitespace character, followed by a newline. Given the string http://www.example.com/\npath/here, your solution will not set $http to 1.

Abigail

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Re: Re: Regex to detect and remove a linebreak in an URL
by Roy Johnson (Monsignor) on May 19, 2004 at 20:02 UTC
    Astonishingly, you are wrong about the character class. [^\w\s] matches characters that are neither words nor whitespace; i.e., punctuation: 
    $_='o.ne<a>tw/o<b>';
@punks = /[^\w\s]/g;
print "<@punks>";

    [download]
    yields 
    <. < > / < >>

    [download]
    The problem with my example was that I left the /g modifier off the pattern match. I've updated it, and tested it: 
    while(<DATA>){
/http:\S*[^\w\s]/g and s/\G\n//;
print;
}
__DATA__
there is an http://whatever.com/address/
crossing/line/boundaries.html right in the
middle of this nice string.

    [download]
    The PerlMonk tr/// Advocate
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      Hello Roy and others,

      What is the X in:

      s/\G\n/X/

      ?

[reply]
        Oh, sorry, that was leftover from some testing. I'm just not having a great brain day today.
        The PerlMonk tr/// Advocate
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