in reply to $foo{bar}-() vs. $foo{bar}()

$above_post =~ s/[1]/[1]/g;

[download]
-Ryan

Replies are listed 'Best First'.
(Ovid - just having a little fun) RE: argh!
by Ovid (Cardinal) on Oct 07, 2000 at 20:11 UTC 
    $above_post =~ s/\[1\]/\\[1\\]/;

    [download]
    In other words, you forgot to escape the brackets, thus creating a character class. Of course, since the right side isn't a regex, it almost looks like we're substituting something back to itself. Weird.

    Sorry. Just couldn't resist :)

    Cheers,
    Ovid

    Join the Perlmonks Setiathome Group or just go the the link and check out our stats.

[reply]
[d/l]
RE: argh!
by rlk (Pilgrim) on Oct 07, 2000 at 20:13 UTC
    Point taken.
    -Ryan
[reply]

In Section Seekers of Perl Wisdom