in reply to Assign & substitute in one statement?
From the Perl Cookbook, recipe 6.1.Copying and Substituting Simultaneously:
You can even use this technique on an entire array:
@bindirs = qw( /usr/bin /bin /usr/local/bin ); for (@libdirs = @bindirs) { s/bin/lib/ } print "@libdirs\n"; __OUTPUT__ /usr/lib /lib /usr/local/lib
The parentheses are required when combining an assignment if you wish to change the result in the leftmost variable. Normally, the result of a substitution is its success: either "" for failure, or the number of times the substitution was done. Contrast this with the preceding examples where the parentheses surround the assignment itself. For example:
($a = $b) =~ s/x/y/g; # copy $b and then change $a $a = ($b =~ s/x/y/g); # change $b, count goes in $a
Update: made a Q&A node of it: How do I assign & substitute in one statement?
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