one
three
five
two
four

• Weell $one is sure to go first.
• $three is sure to go right after $four is created.
• "five" is sure to be printed before $four (or $two) gets cleaned up. I'm not sure the order in which $four and $two will be destroyed (because perl doesn't guarantee order of destruction), but I vaguely recall something about closures going away last, so that's why i'm going with that answer.

  update2: er, actually, forget what i said about closures. two goes before four because the closure is invoked (duh). So I guessed right, but by the time I got to writing down why, things got fuzzy :)(i rushed)