Re^3: Aliasing and return, how does return work?

I'm not sure if lvaluable subs work in 5.6.1. This code works for me with Perl 5.8.4:

sub ret :lvalue { $_[0] }
sub foo {
  &ret++;
  print "ARGS: <@_>\n";
}

my ($x, $y) = (10, 20);
foo($x, $y);
__END__
ARGS: <11 20>
[download]

Make sure you aren't accidentally shifting the argument you're planning on setting before you set it.

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Comment on Re^3: Aliasing and return, how does return work? Download Code

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Re^4: Aliasing and return, how does return work? by bsb (Priest) on Jun 30, 2004 at 06:38 UTC
Got your results with 5.6.1, must be my sketchy understanding at fault. Aha, it was my testing code messing up, reassigning during the middle of the test. Thanks update: I may have spoken too soon...	[reply]