in reply to Re^3: hash problem
in thread hash problem

In that case you get as result 
$VAR1 = {
          'three' => undef,
          'one' => undef,
          'two' => undef
        };

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which isn't at all what the OP asked for.

CountZero

"If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

In Section Seekers of Perl Wisdom