Re^2: Aliasing values, not variables

~~I don't see how this helps the situation at all. He needs to alias one element of an array to another element of the array.~~

Update: hrm, I didn't follow the code properly. Yes, this is a solution to problem. My apologies, Corion.

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Jeff japhy Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and perl hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart

Comment on Re^2: Aliasing values, not variables

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Re^3: Aliasing values, not variables by Corion (Patriarch) on Jul 18, 2004 at 16:31 UTC
It may well be that my solution misses the goal. As far as I understood it, nothingmuch wants two slots in an array to contain the same scalar, and I believe that my subroutine `alias` does that. The routine returns a reference to an array in which the elements are aliased as passed in. So to create an array which aliases the slots 2,3 and 4, you would call it as: `my $v; my $ar = alias("foo","bar",$v,$v,$v,"baz");` [download] Assigning to any of the slots 2,3,4 of `@$ar` will change the other two slots as well, which is how I interpret the question. I might well have misunderstood the question and the problem, as I also don't understand what he needs it for, or rather, what he needs it for prompts different solutions to me.	[reply] [d/l]
Re^4: Aliasing values, not variables by japhy (Canon) on Jul 18, 2004 at 16:43 UTC
You're right. I didn't pay attention to what your function was doing. Your solution can be expanded to work with existing aggregates in a general way. _____________________________________________________ Jeff `japhy` Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and `perl` hacker How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart	[reply]