Re^2: Quantum Weirdness and the Increment Operator

in reply to Re: Quantum Weirdness and the Increment Operator
in thread Quantum Weirdness and the Increment Operator

That is not entirely the case here though. See the following code and output.

my $f = 1;
print '$f = ', $f, ' and $f + $f++ = ', $f + $f++, "\n";

my $g = 1;
print '$g = ', $g;
print ' and $g + $g++ = ', $g + $g++, "\n";

__END__
$f = 2 and $f + $f++ = 3
$g = 1 and $g + $g++ = 3
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This is not the expected behaviour in C and i'm only auto-increment/decrement a single time.

___________
Eric Hodges

Comment on Re^2: Quantum Weirdness and the Increment Operator Download Code

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Re^3: Quantum Weirdness and the Increment Operator by gam3 (Curate) on Mar 30, 2005 at 14:42 UTC
What is undefined is the order of operation. Since ($f + $g++) == ($g++ + $f) this is normally a reasonable assumption, but of course ($f++ + $f) != ($f + $f++). -- gam3 A picture is worth a thousand words, but takes 200K.	[reply]

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