in reply to Re: scalar number with preceding 0.
in thread scalar number with preceding 0.

$s2 is indication for half a second. But that does not have any influence on the result.

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Re^3: scalar number with preceding 0.
by gaal (Parson) on Jul 26, 2004 at 16:44 UTC
    Sounds like you're not using strict... doing that might shed some light on the problem (and indeed on unseen and unforseen ones as well).
[reply]
      I use strict. I have three little ... in my function filling it with life. The weird thing is that even though debugging this I first get the leading zeros, the concatenation kills it. why is that, I cannot see anything describing that effect.
[reply]
        Post more code then.
[reply]

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